If it's not what You are looking for type in the equation solver your own equation and let us solve it.
49x^2-63x=0
a = 49; b = -63; c = 0;
Δ = b2-4ac
Δ = -632-4·49·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-63}{2*49}=\frac{0}{98} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+63}{2*49}=\frac{126}{98} =1+2/7 $
| 80/x=0.8 | | -6(x-3)-26=4 | | 49x^2-62x=0 | | 5=w/2.3 | | 6n^2+6n-14=0 | | 5b–12=18 | | 5-(x/2)=20 | | 2(3)^x+5=45 | | 2(5)^x-6=24 | | 53x+8=252x | | (x+7)/(x+4)=0 | | 5x/4+1/8(x+2)=3 | | 3x-5+2x+19-x=0 | | 5-k=12=16 | | 108-50r=4r | | 4(3-2)=8(2w+3) | | 2(4+r)=8 | | -2(9+2a)-8(4-5a)=-112 | | x4(3x+3)=23 | | 1/2(3/2x+22)-6x=3/4x+2/3 | | 5/y=4 | | 2(1-3x)+2(4x)=24 | | r25=7+r | | (2x-7)-4x+8=4(x+6) | | 2/3(x-4)=3/5(x-3) | | 4x+3(x-2)+5(x+2)=-20 | | 4(x-2)-3(5x+2)=x-14 | | 9(8x+6)=25(x-3) | | -3(n-7)-14=-8 | | 2(3m-4)=9m-11 | | 17.3x15.23=263.479 | | 11/24+1/6a=1/4a |